Theorem 10.3 -The perpendicular from the centre of a circle to a chord bisects the chord. NCERT की कक्षा 9 वीं का गणित के अध्याय 10 वृत्त की प्रमेय 10.3 का हल, हिन्दी माध्यम के छात्रों के लिये<br />NCERT Class 9 Maths Chapter 10 Circles, Proof of Theorem 10.3 for Hindi Medium Students. It is an important theorem for 9th class students. It is useful to acquire 100% marks in board exams.<br /><br />In this video, you will learn and understand the proof of Theorem 10.3 from Class 9 Maths Chapter 10, Circles from NCERT textbook.<br /><br />In this tutorial, you will find the explanation of the following:<br />Class: 9th<br />Chapter: 10<br />Topic: Circles<br />Theorem: 10.3<br />Textbook: NCERT Other channel :- https://bit.ly/2W2F1AM<br />Join Facebook Group:-https://www.facebook.com/groups/aanavcreations/<br />Share link: https://dai.ly/x7vlhms<br /><br /><br /><br /><br /><br /><br /><br /><br /><br />Like us on Facebook:- https://www.facebook.com/learnimperfect/<br />Follow us on instagram and twitter :- @learnimperfect<br />#theorem_10.3_class_9_cbse<br />#class_9_maths_theorem_10.3<br />#theorem<br />#ncert_maths<br />#class_9th_theorem_10.3_proof<br />#theorem_10.3_class_9th<br />#class_9_maths<br />#ncert_maths_class_9<br />#cbse_class_9_maths_chapter_10_circles<br />#chapter_10_circles<br />#cbse<br />#ncert<br />#ncert_maths_class_9_chapter_10<br />#circle_theorems_geometry<br />#प्रमेय_10.3<br />#chapter_10<br />#अध्याय_10<br />#वृत्त<br />#circles<br />#हिन्दी_माध्यम<br />#कक्षा_9<br />#गणित<br />#perpendicular_bisector<br />#chord<br />#center<br />#bisect<br />#cbse_maths<br />#RHS_Creterian<br />#By_CPCT<br />#mid_point<br />#Radius<br />#radii<br />#maths_class_9<br />#mathematics_class_9<br />#maths_class_9_theorem_10.3<br />#maths_class_9_chapter_10_theorem_10.3<br />#theorem_10.3_class_9_maths<br />#maths_class_9_chapter_10<br />#maths_class_9_ex.10.3<br />#ncert_class_9_maths_theorem_10.3<br />#chapter_10_theorem_10.3<br />#class_9_theorem_10.3<br />#theorem_10.3_class_9<br />#class_9_chapter_9<br />#ex_10.3_class_9<br />#class_9_maths_chapter_9_exercise_10.3<br />#exercise_10.3_class_9<br />#chapter_9_class_9_maths<br />#ex_10.3_class_9_maths<br />#class_9_maths_chapter_9_theorem_10.3<br />#mathsteacher_class_9_chapter_9_maths<br />#exercise_10.3_class_10_maths<br /><br /> Disclaimer -<br /><br />video is for educational purpose only.Copyright Disclaimer Under Section 107 of the Copyright Act 1976, allowance is made for "fair use" for purposes such as criticism, comment, news reporting, teaching, scholarship, and research. Fair use is a use permitted by copyright statute that might otherwise be infringing. Non-profit, educational or personal use tips the balance in favour of fair use.
